Question

Use a suitable identity -2x+3y+2z^2

Answer 1

Answer:

(a+b+c)^2 = a×a + b×b+ c×c +2ab +2bc +2ca

Here

a= -2x

b=3y

c= 2z

So putting the values of a,b and c in the identity, we get

=(-2x × -2x) + (3y×3y) + (2z×2z) + 2(-2x)(3y) + 2(3y)(2z) + 2(2z)(-2x)

= 4x^2 + 9y^2 + 4z^2 -12xy +12yz -8xz

This is the answer