Use a suitable identity to get each of the following products.
(i) (x + 3) (x + 3)
(ii) (3a – ½)(3a – ½)
Answers
Answered by
0
Answer:
Step-by-step explanation:
1) (x + 3) (x + 3)
= ( x + 3 )² [∵(a + b)² = a²+ 2ab + b² ]
= x² + 2 ( x ) ( 3 ) + ( 3 )²
= x² + 6x + 9 is the answer.
2)(3a - 1/2) ( 3a - 1/2)
= ( 3a - 1/2 )² [∵( a- b )² = a² - 2ab + b² ]
= ( 3a )² - 2 ( 3a ) ( 1/2 ) + ( 1/2 )²
= 9a² - 3a + 1/4 is the answer.
Answered by
0
Answer:
(¡) (x+3)(x+3)
let a=x and b=3
= (x+3)²
we know that,
(a+b)²= (a²+b²+2ab)
(x+3)²=(x²+3²+2×x×3)
=x²+9+6x
(¡¡) (3a-1/2)(3a-1/2) (same as (¡)
we know that
(3a-1/2)(3a-1/2)=(3a-1/2)²
(3a-1/2)²={3a²+(1/2)²+2×3a×(-1/2)}
=9a²+1/4+6a×(-1/2)
=9a²+1/4-3a
Hope it's correct:)
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