Question

use completing of square method on it
1) 4x²+4√3x+3=0
2) 2x²+x-4=0

Answer 1

1
4x2+2√3x+2√3x+3
2x(2x+√3) √3(2x + √3)
(2x + √3) (2x + √3)
=0

Answer 2

♤♤hey frnds.....

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1) this solution is in this pic ⬆️⬆️⬆️.


2)
$2x^{2} + x - 4 = 0$
${x}^{2} + \frac{x}{2} - \frac{4}{2} = 0$
${x}^{2} \times 2 \times x \times \frac{1}{4} + \binom{1}{4}^{2} - \binom{1}{4}^{2} + 2 = 0$
$\binom{x + 1}{4}^{2} = \binom{1}{4}^{2} + 2$
$\binom{x + 1}{4}^{2} = \frac{1}{16} + 2$
$\binom{x + 1}{4}^{2} = \frac{x + 32}{16}$
$\frac{x + 1}{4} = \sqrt{ \frac{33}{16} }$
$x + \frac{1}{4} = + - \frac{ \sqrt{33} }{4}$
Now , we use add (+) ...

$x = \frac{ - 1}{4} + \frac{ \sqrt{33} }{4}$
$x = \frac{ - 1 + \sqrt{33} }{4}$
then , using subtract (-) ...

$x = \frac{ - 1}{4} - \frac{ \sqrt{33} }{4}$
$x = \frac{ - 1 - \sqrt{33} }{4}$


Hence ans is :-
$x = \frac{ - 1 + \sqrt{33} }{4} and \: x = \frac{ - 1 - \sqrt{33} }{4}$



$i \: hope \: its \: helpful$
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