Use congruency of triangles to find the values of x and y in each of the following figures:
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c) In ∆ABE and ∆ DBC
AB= BC (given)
Angle A = Angle C (given)
AE = DC (given)
So, ∆ ABE congruent to ∆DBC [by SAS congruence Rule]
So, by CPCT,
Angle ABE = Angle DBC
Hence y°= 20°
d) x+10° = y+20° (opposite sides of a rectangle are equal)
i.e. AC = BD
Now, In ∆ ABD and ∆ACD
AB = CD (given)
Angle B = Angle C = 90° (given)
AC= BD (proved above)
So, ∆ABD congruent to ∆ACD (by SAS congruence Rule)
By CPCT,
Angle BAD = Angle CDA
i.e. x= 50°
HOPE IT HELPS.
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Answer:
- x=3 and y=20
- x=50 and y=40
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