USE ECLID'S DIVISION ALOGARITHM TO FIND THE H.C.F OF I)900,270 ii)38220,196 iii)2032,1651
Answers
Answered by
3
Answer:
1) 900 and 270, start with the larger
900 and 270, start with the largerinteger, that is 900. Apply the
900 and 270, start with the largerinteger, that is 900. Apply theDivision lemma, we get
900 and 270, start with the largerinteger, that is 900. Apply theDivision lemma, we get900 = 270 x 3 + 90
900 and 270, start with the largerinteger, that is 900. Apply theDivision lemma, we get900 = 270 x 3 + 90270 = 90 x 3 + 0
900 and 270, start with the largerinteger, that is 900. Apply theDivision lemma, we get900 = 270 x 3 + 90270 = 90 x 3 + 0The remainder has now become
900 and 270, start with the largerinteger, that is 900. Apply theDivision lemma, we get900 = 270 x 3 + 90270 = 90 x 3 + 0The remainder has now becomezero. Now our procedure stops.
900 and 270, start with the largerinteger, that is 900. Apply theDivision lemma, we get900 = 270 x 3 + 90270 = 90 x 3 + 0The remainder has now becomezero. Now our procedure stops.Since the divisor at this stage is 90.
900 and 270, start with the largerinteger, that is 900. Apply theDivision lemma, we get900 = 270 x 3 + 90270 = 90 x 3 + 0The remainder has now becomezero. Now our procedure stops.Since the divisor at this stage is 90.Therefore,
900 and 270, start with the largerinteger, that is 900. Apply theDivision lemma, we get900 = 270 x 3 + 90270 = 90 x 3 + 0The remainder has now becomezero. Now our procedure stops.Since the divisor at this stage is 90.Therefore,HCF ( 900, 270 ) = 90
Step-by-step explanation:
PLEASE MARK ME AS A BRAIN LIST MATE!!!!!
Answered by
1
Similar questions