Math, asked by manoj257, 1 year ago

use Eclids algorithm to finds HCF of 1190 and 1445 . Express the HCF in form of 1190m+1445n

Answers

Answered by Anonymous

1

A= bq + r
1445= 1190× 1 + 255
1190 = 255 × 4+ 170
255 = 170 × 1 + 85
170 =,85× 2 +0
So the hcf of 1445 and 1190 is 85

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