Use euclid division algorithm to find the hcf of 210 and 55 if hcf is expressible in the form of 210x+55y find x and y
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Answered by
222
the HCF of 210 and 55
210=55*3+45
55=45*1+10
45=10*4+5
10=5*2+0
therefore 5 is the hcf
5=210x+55y
Answered by
165
Solution :-
HCF of 210 and 55
Using Euclid's division algorithm.
210 = (55*3) + 45
55 = (45*1) + 10
45 = (10*4) + 5
10 = (5*2) + 0
So, the remainder is 0 at the last stage, so HCF of 210 and 55 is 5.
∴ 5 = (210*5) + 55y
⇒ 5 = 1050 + 55y
⇒ - 55y = 1050 - 5
⇒ - 55y = 1045
⇒ y = - 1045/55
⇒ y = - 19
Hence, the value of x is 5 and y is - 19
Answer.
HCF of 210 and 55
Using Euclid's division algorithm.
210 = (55*3) + 45
55 = (45*1) + 10
45 = (10*4) + 5
10 = (5*2) + 0
So, the remainder is 0 at the last stage, so HCF of 210 and 55 is 5.
∴ 5 = (210*5) + 55y
⇒ 5 = 1050 + 55y
⇒ - 55y = 1050 - 5
⇒ - 55y = 1045
⇒ y = - 1045/55
⇒ y = - 19
Hence, the value of x is 5 and y is - 19
Answer.
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