use Euclid division algorithms find HCF of 274140 and 17017
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Heya!!
==>>HCF (274170, 17017)
274170 = 17017*16 + 1898
17017 = 1898*8 + 1833
1898 = 1833*1 + 65
1833 = 65*28 + 13
65 = 5*13 + 0
So, HCF (274179, 17017) = 13
Hope this helps you ☺
==>>HCF (274170, 17017)
274170 = 17017*16 + 1898
17017 = 1898*8 + 1833
1898 = 1833*1 + 65
1833 = 65*28 + 13
65 = 5*13 + 0
So, HCF (274179, 17017) = 13
Hope this helps you ☺
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