Use Euclid division lemma to find hcf of 650,1170
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1170=650*1+520
650=520*1+130
520=130*4+0
.•.The hcf of 1170 and 650 is 130. (and)
650=520*1+130
520=130*4+0
.•.The hcf of 1170 and 650 is 130. (and)
Answered by
6
Answer:
- The divisor at this stage, ie, 130 is the HCF of 1170 and 650.
Given :
- The numbers 1170 and 650.
To find :
- HCF of 1170 and 650 by Euclid method =?
Step-by-step explanation:
Clearly, 1170 > 650
Applying the Euclid's division lemma to 1170 and 650, we get
1170 = 650 x 1 + 520
Since the remainder 520 ≠ 0, we apply the Euclid's division lemma to divisor 650 and remainder 520 to get
650 = 520 x 1 + 130
We consider the new divisor 520 and remainder 130 and apply the division lemma to get
520 = 130 x 4 + 0
Now, the remainder at this stage is 0.
So, the divisor at this stage, ie, 130 is the HCF of 1170 and 650.
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