use euclid division lemma to show that any positive odd integer is of the form 6q+1 or6q+3 or 6q+5, where q is some of the integers
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Let us assume that 'a' is an integers. ( 'a' can be either odd or even number )
Euclid's division lemma - a = bq+r ( 0 ≤ r < b )
Here in this case b=6
⇒ a = 6q+r ------ equation one
If b = 6 then -
(r=0) or (r=1) or (r=2) or (r=3) or (r=4) or (r=5)
Let r=0
⇒ a = 6q+r
⇒ a = 6q+0
⇒ a = 6q
∴ a is even number
let r=1
⇒a = 6q+1
∴ a is odd number
let r=2
⇒a = 6q+2
∴ a is even number
let r=3
⇒ a = 6q+3
∴ a is odd number
let r=4
⇒ a = 6q+4
∴ a is even number
let r=5
⇒ a = 6q+5
∴ a is odd number
∴ a is an odd positive integer of the form 6q+1 (or) 6q+3 (or) 6q+5
Hence proved.
Euclid's division lemma - a = bq+r ( 0 ≤ r < b )
Here in this case b=6
⇒ a = 6q+r ------ equation one
If b = 6 then -
(r=0) or (r=1) or (r=2) or (r=3) or (r=4) or (r=5)
Let r=0
⇒ a = 6q+r
⇒ a = 6q+0
⇒ a = 6q
∴ a is even number
let r=1
⇒a = 6q+1
∴ a is odd number
let r=2
⇒a = 6q+2
∴ a is even number
let r=3
⇒ a = 6q+3
∴ a is odd number
let r=4
⇒ a = 6q+4
∴ a is even number
let r=5
⇒ a = 6q+5
∴ a is odd number
∴ a is an odd positive integer of the form 6q+1 (or) 6q+3 (or) 6q+5
Hence proved.
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