Use Euclid division lemma to show that the square of any positive integer is of the form of 4k, 4k+1
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Step-by-step explanation:
let b=2
by lemma ,a=bq+ r
a= 2q + r where r can be 0,1
let r= 0
a= 2q + 0
squaring on both side
a^2 = (2q)^2
a^2= 4q^2
let q^2 be k
hence , a^2=4k
let r=1
a=2q+l
S.O.B
a^2=(2q+1)^2
a^2= 4q^2+4q+1
= 4(q^2+q)+1
let, (q^2+q) be k
hence,a^2= 4k+1
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