Question

use euclid's algorithm to find the HCF of 4052 and 12576​

Answer 1

Answer:

12576=4052×3+420

4052=420×9+272

420=272×1+248

272=148×1+124

148=124×1+24

124=24×5+4

24=4×6+0

Answer 2

Answer:

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