Use euclid's algorithm to find the hcf of 4052 and 12578
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4052)12576(3
12154
-------------
420)4052(9
3780
-------------
272)420(1
272
-------------
148)272(1
148
-------------
124)148(1
124
-------------
24)124(5
120
-------------
(4)24(6
24
-------------
0
=> HCF = 4
12154
-------------
420)4052(9
3780
-------------
272)420(1
272
-------------
148)272(1
148
-------------
124)148(1
124
-------------
24)124(5
120
-------------
(4)24(6
24
-------------
0
=> HCF = 4
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