use euclid's division algorithm to find the HCF of 1288 and 575
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Answer:
Hello ♥️♥️♥️
Step-by-step explanation:
As We know that
_______________________
Euclid's division algorithm
Let a and b be the two positive
integer then there exists two unique
whole number q and r such that
a=bq+r
Where,0<_r<b
___________________________
Applying division algorithm to 1288 and 575
1288=575×2+135
575=134×4+23
134=23×6+0
The remainder has now bacome
Zero , so our procedure stop.
since the division at this stage is 23
The HCF of 1288 and 575 is 23
- Hope it help uh
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