use Euclid's division algorithm to find the HCF of 135 and 125
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Answered by
30
hey dear
by using Euclid's division algorithm a= bq+r
135=125+1+10
125=10×12+5
10= 5×2+0
so hcf of 135 and 125 is 5
Hope helps you
by using Euclid's division algorithm a= bq+r
135=125+1+10
125=10×12+5
10= 5×2+0
so hcf of 135 and 125 is 5
Hope helps you
Answered by
4
135 = 135*1+90
Remainder =0
Remainder =0
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