Question

Use Euclid's division lemma to show that the square of any positive integer is of the form
3p. 3p+.​

Answer 1

Step-by-step explanation:

Let a be any positive integer

b = 3

by Euclid division lemma a =3p ,3p+1,3p+2

a^2=(3p)^2

=9p^2

a^2=3(3p)^2

a^2=(3p+1)^2

=9p^2+6p+1

=3p(3p+2)+1

a^2=3p+1

a^2=(3p+2)^2

=9p^2+12p+4

=(9p^2+12p+3)+1

=3(3p^2+4p+1)+1

=3p+1

hence,the square of any positive integer is of the form 3p and 3p+1

hope this will help you

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Answer 2

plz refer to this attachment