Question

Use Euclid's logarithms to find the HCF of 900and 270

Answer 1

Answer:

Step-by-step explanation:

Euclid's division lemma - a=bq+r (0<=r<b)

Here 900>270...so

900=270 x 3 +90

270=90 x 3 + 0

Therefore 90 is the HCF of 900 and 280

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Answer 2

Answer:

Euclid's division lemma:-

Let A and B be any two positive integers then 3 exists 2 unique whole numbers q and r

Such that.

a = bq + r

0 < r < b

Now,

900 and 270 start with the larger integers that is 900.

Apply the division lemma we get.

900 = 270 × 3 + 90

270 = 90 × 3 + 0

The remainder has now become 0.

Now, our procedure stops.

Since the division at this stage is 90.

Therefore, H.C.F(900, 270) = 90

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