use euclids algorith to find hcf of 4052 and 12576
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here is your answer by Sujeet
a=bq+r
12576=4052*3+420
4052=420*9+272
420=272*1+148
272=148*1+124
148=124*2+0
hcf of 12576 & 4052...
that's all
Sujeet
a=bq+r
12576=4052*3+420
4052=420*9+272
420=272*1+148
272=148*1+124
148=124*2+0
hcf of 12576 & 4052...
that's all
Sujeet
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