use euclids divison algorithm to find the hcf of 4052 and 12576
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the hcf of the given two numbers us
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HCF of 12576 and 4052
12576 = 4052 × 3 + 420
4052 = 420 × 9 + 272
420 = 272 × 1 + 148
272 = 148 × 1 + 124
148 = 124 × 1 + 24
124 = 24 × 5 + 4
24 = 4 × 6 + 0
Therefore HCF = 4..... HCF = b
hope it helps
HCF of 12576 and 4052
12576 = 4052 × 3 + 420
4052 = 420 × 9 + 272
420 = 272 × 1 + 148
272 = 148 × 1 + 124
148 = 124 × 1 + 24
124 = 24 × 5 + 4
24 = 4 × 6 + 0
Therefore HCF = 4..... HCF = b
hope it helps
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