Question

use exponential notation
x = (3/4)^3 (4/3)^5
y = (2^-2 + 3^-2 + 4^-1)
(1) Find the value of x + y
(2) Find the value of x/y

someone pls answer with explanation​

Answer 1

Answer:

x= (3/4)^3.( 4/3)^5

x= (3/4)^3.(3/4)^-5

x= (3/4)^3-5

x= (3/4)^-2 = (4/3)^2= 16/9

y= 1/4+ 1/9+1/4 = 1/2+1/9

= 11/18

1)x+y= 16/9+ 11/18

= 32+11/18

= 43/18

2) x/y = 16/9÷11/18= 16/9×18/11

= 32/11