Use factor theorem to prove that x + is a factor of x and + 1 for any odd positive integer n
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use factor theorem to prove that
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Step-by-step explanation:
༆ ɑnswer ࿐
let p(x) = x^n + a^n , Where n is odd positive integer
g(x) = x + a
= x + a = 0
= x = — a
p(—a) = (—a)^n + (a)^n
= —a^n + a^n
= 0
since is odd number
therefore by factor theorem m, x + a is a factor of p(x) Where n is odd positive integer...
hope it may help you
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