Question

use ideal to show that the square any positive integer is form 3p, 3p+1

Answer 1

Answer:

Step-by-step explanation:

Using Euclid division lemme

Integer is of form 3q 3q+1 and 3q+2

(3q)^2=9q^2 =3p where p=3q2

(3q+1)^2=9q^2+1+6q=3p+1 where p=3q^2+2q

(3q+2)^2=9q^2+4+12q=3p+1 where p=3q^2+4q+1

Plz mark brainliest