Question

use kirchhoff's rule to determine the potential difference between the point A and D when no current flow through arm BE of the electronic network ​

Answer 1

Answer :-

Let us apply Kirchoff's rule at B.

i3 = i1 + i2

It is mentioned that,  no current flow through arm BE.

So i2 = 0

Hence I3 = i1

By applying 2nd law on AFEB, we get

i3 x 2 + i3 x 3 + i2 x R1 = 1 + 3 + 6

i2 = 0,

So 5 x i3 = 10

i3 = 2 A

Hence i1 = 2A

Potential Difference between A to D = 2i3 - 1 + 3 x i3

Potential Difference between A to D = 9V