Use mathematical induction to prove that statement,1²+2²+3³+.....+n²=n(n+1)(2n+1)/6
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Step-by-step explanation:
in 1st case n=1
n(n+1)(2n+1)/6=n^2
1(1+1)(2*1+1)/6=1^2
1(2)(3)/6=1
6/6=1
1=1
LHS=RHS
in 2nd case n=k
1^2+2^2+3^3+........+n^2=(n+1)(2n+1)/6
1^2+2^2+3^3+........+k^2=(k+1)(2k+1)/6
=2k^2+3k+1/6....eq1
in 3rd case n=k+1
1^2+2^2+3^3+........+k+1^2=(k+1+1) (2(k+1)+1)/6
1^2+2^2+3^3+........+k+1^2=(k+2)(2k+3)/6...eq2
substitute
2k^2+3k+1/6+(k+1)^2=3k^2+7k+6/6
2k^2+3k+1+(6k+6)^2=3k^2+7k+6
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