use remainder theorem to find the remainder when x^3-6x^2-4 is divided by 1-3/2 x
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remainder theorem : when any polynomial P(x) is divided by another polynomial g(x) = (x - a), then remainder obtained is P(a).
here P(x) = x³ - 6x² - 4 and g(x) = 1 - (3/2)x
firstly, find value of x at g(x) = 0
g(x) = 1 - (3/2)x = 0
or, x = (2/3)
now from remainder theorem
remainder will be P(2/3)
P(2/3) = (2/3)³ - 6(2/3)² - 4
= (2³/3³) - 6(2²/3²) - 4
= 8/27 - 6 × 4/9 - 4
= 8/27 - 8/3 - 4
= (8 - 72 - 108)/27
= -172/27
hence, answer will be -172/27
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