Question

Use remainder theorem to find the value of k.It being given that x³+2x²+kx+3 is divisible by x-3.Then the remainder is 21.[Don't spam]

Answer 1

Answer:

using remainder theorem

x = 3

x^3 + 2x^2 + kx + 3 = 21

( 3 )^3 + 2 ( 3 )^2 + k ( 3 ) + 3 = 21

27 + 18 + 3k + 3 = 21

3k = 21 - 48

3k = - 27

k = - 27 / 3

k = - 9

(Please mark me as brainlist answer)

Answer 2

Answer:

-9

Step-by-step explanation:

p(x) = x³ + 2x² + kx + 3

g(x) = x - 3

x - 3 = 0

x = 3

Substitute this in p(x)

x³ + 2x² + kx + 3

(3)³ + 2(3)² + k(3) + 3 = 21

27 + 18 + 3k + 3 = 21

3k = 21 - 48

k = -27 /3

k = -9

HOPE THIS ANSWER HELPS U...