Question

Use remainder threom factorise the following. 2x^3+x^2-13x+6.

Answer 1

Hello Dear!!!

Here's your answer...

Given that,

p(x) = x^3 + 3x^2 - 5x +4

Zero of (x-2) is

x-2 = 0

x = 2

substitute the value of x in p(x)

p(2) = (2)^3 + 3(2)^2 -5(2)+4

p(2) = 8 + 3(4) - 10 +4

p(2) = 8+12-10+4

p(2) = 14

Remainder is 14.

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Hope this helps you....

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