use short cut to find (a) 11×11-10×10 , (b) 25×25-24×24,(c) 139×139-138×138
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hey mate!!
here is your answer:
you can use the identity of a^2-b^2=(a-b)(a+b)
a)11×11-10×10=11^2-10^2=(11-10)(11+10)=1×21=21
b)25×15-24×24=25^2-24^2=(25-24)(25+24)=1×49=49
c)139×139-138×138=139^2-138^2=(139-138)(139+138)=1×277=277
hope it helped!
here is your answer:
you can use the identity of a^2-b^2=(a-b)(a+b)
a)11×11-10×10=11^2-10^2=(11-10)(11+10)=1×21=21
b)25×15-24×24=25^2-24^2=(25-24)(25+24)=1×49=49
c)139×139-138×138=139^2-138^2=(139-138)(139+138)=1×277=277
hope it helped!
7766035121rk:
correct
Answered by
1
277 is the answers of questions
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