Question

use suitable identities to solve the following 103 into 9

Answer 1

Hey here is your answer
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The identity used here is

= (a+b)×c
= ac + bc

$= 103 \times 9 \\ \\ = (100 + 3) \times 9 \\ \\ =( 100 \times 9) + (3 \times 9) \\ \\ = 900 + 27 \\ \\ = 927$
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