Question

use superposition principle to find voltage v0.



plzz can any one solve this

Answer 1

To solve a circuit using superposition, the first step is to turn off or suppress all but one input.

1 ) To suppress a voltage source, replace it with a short circuit.
2 ) To suppress a current source, replace it with an open circuit.

Then you analyze the resulting simpler circuits. Repeat for all inputs.

The final result is the sum of individual results.

When I = 0 , (we are only taking v source)

V = I× R
I1 ( flowing through 2k ohm resistor) = 10/(2k +2k) = 0.0025A

When V = 0 (we are only taking I)

Then current Flowing through 2kohm resistor

I2 =[{(2k+2k)/(2k×2k)}×2×10^3A]/(2k)
I2 = 10^-6A

Total Current flowing Through 2k ohm resistor
I1 + I2 = 0.0025 + 10^-6

V0 = I×R = (0.0025+10^-6) × 2000
V0 = 5

what the Need to use Superposition when you can Use simple V = IR and Find V0

Total Resistance of Circuit = 2k + 2k = 4k
Current flowing in Circuit = 10/4k
V0 = (10/4k) × 2k
V0 = 5v

Hope you Didn't Understand!