Use the discriminant to determine how many real number solutions exist for the quadratic equation −4j2 + 3j − 28 = 0. A. 2 B. 0 C. 1 D. 3
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Answer:
Step-by-step explanation:
discriminant = 9 - 16*28 = - 439 < 0.
NO real solutions.
Option B
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ans is B. 0
it is because when u keep the values in D=b²-4ac
you will get (-ve) value and no soln. for negative value
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