Question

Use the discriminant to determine the number of real roots the equation has. 3x2 – 5x + 1 =0

(a) One real root (a double root),

(b) Two distinct real roots,

(c) Three real roots,

(d) None (two imaginary roots)​

Answer 1

Answer:

hii

your answer is here !

Step-by-step explanation:

Discriminant = bx^2 – 4ac

Compare the above equation 3x^2 – 5x + 1 =0 with ax^2 + bx + c = 0

We get, a = 3, b = -5, c = 1

Put the value of a, b and c;

Discriminant = bx^2 – 4ac

Discriminant = (-5)^2 - 4 × 3 × 1

= 25 – 12

= 13 [13 > 0]

Therefore, discriminant is positive.

So the given equation has two distinct real roots.

option (B) is right answer !

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Answer 2

Given

3x^2 - 5x + 1 = 0

let

A = 3

B = -5

c = 1

we know that

D = (b^2 - 4ac )

D = (- 5)^2 - 4*3*1)

D = (25 - 12)

D = 13

so

D> 0

so the two distinct real root possible

option B is right ✔️✔️