Use the explicit formula a, = a + (n-1).D to find the 350th term of the sequence below. 57, 66, 75, 84, 93,
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a=57
d=66-57=9
an=a+(n-1)d
350th term =57+(350-1)×9
=57+(349)×9
=57+3141
= 3198
so the 350th term =3198
d=66-57=9
an=a+(n-1)d
350th term =57+(350-1)×9
=57+(349)×9
=57+3141
= 3198
so the 350th term =3198
Answered by
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a (first term) = 57
d (common difference) = 2nd term-1st term = 66-57 = 9
n = 350
350th term = 57 + (350-1) 9
=57 + 3141
=3198
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