Math, asked by vaishu1711, 1 year ago

use the formula a^2-b^2=(a+b)(a-b) to find the factor of (81x^2-64y^2)

Answers

Answered by Avijith
2

81x²·64y² can be written as

(9x)²- (8y²) so from this using the a²·b² formula⇒

(9x+8y) × (9x-8y)

so here is your 2 factors of the quadratic equation


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