Use the remainder theorem to factorise the following expression :
2x³ + x² - 13x + 6
Answers
Heya!!
Here's your answer!!
Let f(x) = 2x³ + x² - 13x + 6
Put x = 2,
f(2) = 2(2)³ + 2² - 13(2) + 6 = 0, satisfied.
Hence (x-2) is a factor of f(x) x-3
2x² + 5x -3
__________________
x - 2 ) 2x³ + x² - 13x + 6
2x³ - 4x²
- +
________________
5x² - 13x
5x² - 10x
- +
________________
- 3x + 6
- 3x + 6
+ -
____________
0
____________
Thus,. f(x) = (x-2) (2x² + 5x - 3)
= (x - 2) (2x² + 6x - x - 3)
= (x -2) [2x ( x+3) - 1(x+3)]
= (x-2) (x +3) (2x-1).
Glad help you,
it helps you,
thanks.