Question

Usha bought a cycle for ₹720 and sold it for ₹698.4,find the lost percent

Answer 1

Answer:

Usha faced loss of 3%.

Step-by-step explanation:

Given:

Usha brought the cycle for Rs. 720

Sold it for Rs. 698.4

To find:

Loss%

Solution:

Selling Price = Rs. 698.4

Cost Price = Rs. 720

Cost Price > Selling Price

∴ Loss is incurred.

⇒ Loss% = (CP - SP)/SP × 100

⇒ Loss% = (720 - 698.4)/720 × 100

⇒ Loss% = 21.6/720 × 100

⇒ Loss% = 2160/720

⇒ Loss% = 216/72

⇒ Loss% = 3

Therefore, Usha faced loss of 3%.

Answer 2

$\large\underline{\sf{Solution-}}$

Given that,

Usha bought a cycle for ₹720 and sold it for ₹698.4.

It means,

Selling Price of cycle is ₹ 698.40

Cost Price of cycle is ₹ 720

Since, Cost Price > Selling Price

So, it implies, there is loss in this transaction.

Now, we know that

$\rm \: Loss = Cost \: Price - SellingPrice$

So, on substituting the values of Cost Price and Selling Price, we get

$\rm \: Loss = 720 - 698.40$

$\rm\implies \:Loss = 21.6$

Now, We know that,

$\boxed{\sf{ \:\rm \: Loss \: \% \: = \: \dfrac{Loss}{Cost \: Price} \times 100 \: \% \: \: }}$

So, on substituting the values, we get

$\rm \: Loss \: \% \: = \: \dfrac{21.6}{720} \times 100 \: \%$

$\rm \: Loss \: \% \: = \: \dfrac{216}{7200} \times 100 \: \%$

$\rm \: Loss \: \% \: = \: \dfrac{216}{72} \: \%$

$\rm\implies \: \: \boxed{\sf{ \: \: \rm \: Loss \: \% \: = \: 3 \: \% \: \: }}$

Hence,

Usha bought a cycle for ₹720 and sold it for ₹698.40, the loss % is 3 %.

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$\begin{gathered}\: \: \: \: \: \: \begin{gathered}\begin{gathered} \footnotesize{\boxed{ \begin{array}{cc} \small\underline{\frak{\pmb{ \red{More \: Formulae}}}} \\ \\ \bigstar \: \bf{Gain = \sf S.P. \: – \: C.P.} \\ \\ \bigstar \:\bf{Loss = \sf C.P. \: – \: S.P.} \\ \\ \bigstar \: \bf{Gain \: \% = \sf \Bigg( \dfrac{Gain}{C.P.} \times 100 \Bigg)\%} \\ \\ \bigstar \: \bf{Loss \: \% = \sf \Bigg( \dfrac{Loss}{C.P.} \times 100 \Bigg )\%} \\ \\ \\ \bigstar \: \bf{S.P. = \sf\dfrac{(100+Gain\%) or(100-Loss\%)}{100} \times C.P.} \\ \: \end{array} }}\end{gathered}\end{gathered}\end{gathered}$