Question

usha swims in 90 m long pool. she covers 180m in 1 minute by swimming for one end to other and back along the same straight path. estimate the average speed and average velocity of usha.​

Answer 1

Answer:

Average speed= 3 m/s

Average velocity = 0 m/s

Explanation:

Given:

Distance of the swimming pool = 90 metres

Distance while going and coming back = 180 metres

Time taken to go and come back = 1 minute = 60 seconds

To find:

• Average speed
• Average velocity

Average speed:

Average speed = $\frac{Total \ distance}{Total \ time}$

Average speed = $\frac{180}{60}$

Average speed = 3 m/s

The average speed of Usha is equal to 3 m/s

Average velocity:

The total displacement will be equal to 0 as usha comes back to her initial position after swimming

Average velocity = $\frac{Total \ displacement}{Total \ time}$

Average velocity = $\frac{0}{60}$

Average velocity = 0 m/s

The average velocity of Usha is equal to 0 m/s

Answer 2

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