Question

Usha swims in a 90 m long
pool. She covers 180 m in one minute
by swimming from one end to the other
and back along the same straight path.
Find the average speed and average
velocity of Usha.​

Answer 1

Answer:

khushbooyadav112006 Ambitious

Distance = 180 m

Time = 1 min = 60sec

Average speed = total distance covered / total time taken

= 180m / 60 sec

= 3m/s

Displacement = 0m/s ( as usha come back along the same path so, the intial and final position is same )

Average velocity = displacement/ time

= 0m / 60 s

= 0m/s

Answer 2

Answer:

0 and 3m/s

Explanation:

Average velocity os zero because velocity =Displacement between statring to stoping points/time taken,

displacement is zero

Average speed =total distace/total time=180m/60s=3m/s