Physics, asked by TheUnknownLily, 4 months ago

Usha swims in a 90 m long pool . She covers 180 m in one minute by swimming from one end to the other end and back along the same straight path . Find the velocity and acceleration of Usha .​

Answers

Answered by mk8926391
1

Answer:

both are zero

because

velocity will be zero

as both initial and final positions were same

Explanation:

mark me as brainliest

Answered by Anonymous
7

 \star\underline{\mathtt\orange{⫷❥Q᭄} \mathfrak\blue{u~ }\mathfrak\blue{Σ} \mathbb\purple{ §}\mathtt\orange{T} \mathbb?\pink{iOn⫸}}\star\:

Usha swims in a 90 m long pool . She covers 180 m in one minute by swimming from one end to the other end and back along the same straight path . Find the velocity and acceleration of Usha

\star\underbrace{\mathtt\red{⫷❥ᴀ᭄} \mathtt\green{n~ }\mathtt\blue{ §} \mathtt\purple{₩}\mathtt\orange{Σ} \mathtt\pink{R⫸}}\star\:

displacement(d) = 0

(because \: she \: starts \: and \: ends \: at \: the \:  \\ same \: point)

time \: taken(t) = 60 \: sec \\ (1 \: min = 60 \: sec)

velocity =  \frac{d}{t}

 =  \frac{0}{60}

{\boxed {\boxed {velocity = 0 \: m/s}}}

acceleration =  \frac{v - u}{t}

here \: velocity = 0

 =  \frac{0}{60}

{\boxed {\boxed {acceleration = 0 \:  {m/s}^{2}}}}

 \blue{\boxed{\blue{ \bold{\fcolorbox{red}{black}{\green{☺︎︎Hope\:It\:Helps☺︎︎}}}}}}

 {\mathbb{\colorbox {orange} {\boxed{\boxed{\boxed{\boxed{\boxed{\colorbox {lime} {\boxed{\boxed{\boxed{\boxed{\boxed{\colorbox {aqua} {@suraj5069}}}}}}}}}}}}}}}

Similar questions