Question

what is the length of the hypotenuse of a right triangle if each of the two legs is 4 units?
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Answer 1

Given :

⬤ Two legs of Right Tringle are of 4 units .

To Find :

⬤ Length of Hypotenuse.

Formula Used :

$\sf[\:{{(Hypotenuse)}^{2}={(Base)}^{2}+{(Perpendicular)}^{2}\:]}$

Solution :

According to the Formula :

(H)² = (B)² + (P)²

(AC)² = (BC)² + (AB)²

(AC)² = (4)² + (4)²

(AC)² = (4×4) + (4×4)

(AC)² = 16 + 16

(AC)² = 32

AC = √32

AC = 5.65

Therefore , The Length of the Hypotenuse of the Right angle Tringle is 5.65 cm .

Answer 2

Answer:

$\sqrt{32}$

Step-by-step explanation:

(h×h) = (b×b) + (p×p)

==> h×h = (4×4) + (4×4)

==> h×h = 16 + 16

==> h×h = 32

& h =

$\sqrt{32}$