Usha swims in a 90 m long pool. She covers 180 m in one minute by swimming from one end to the other and back along the same straight path. Find the average speed and average velocity of Usha
NCERT Class IX
Sciences - Main Course Book
Chapter 8. Motion
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total distance covered by Usha in 1min is 180 s
displacement of Usha in 1min=0m
average speed= distance/time
=180/60m/s
average velocity= displacement/time
=0m/60s=0m/s
hope it helps uu ☺☺☺☺
displacement of Usha in 1min=0m
average speed= distance/time
=180/60m/s
average velocity= displacement/time
=0m/60s=0m/s
hope it helps uu ☺☺☺☺
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