Question

Usha swims in a 90 metre long pool she covers 180 m in 1 minute by swimming from one end to the other and back along the same straight path find the average speed and average velocity of Usha

Answer 1

Distance = 180 m
Displacement = 0 (returned to initial position)
time taken 60 s
Avg speed = total distance/total time
= 180/60
=3 m/s
avg velocity = displacement/ time
=0/60
=0m/s

Answer 2

Answer:

Average speed = 3 ms⁻¹

Average velocity = 0 ms⁻¹

Explanation:

Total distance covered by usha in 1 minute = 180 metres

Displacement of Usha in 1 minute = 0 metres

Average speed = Total distance covered / total time taken

= 180/1 min

1 min = 60 seconds

180/60 = 3 m s⁻¹

Average velocity = Displacement / time taken

0/60 seconds

= 0ms⁻¹

The average speed of Usha is 3 ms⁻¹ and average velocity is 0 ms⁻¹