Question

Usha swimvs in 90metre long poolshe swim 180metre in 1 minute from one end to another then find the avrage speed and avrage velocity

Answer 1

Hello dear friend,

The answer to ur question is................
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Here , given is that
distance covered by usha , d   = 180 m
displacement, s = 90-90=0 (∴ s = final position - initial position)
time taken, t=  1 minute = 60 seconds

now,
∵average speed = total distance covered /total time taken by usha 
= 180m /60 seconds
∴ 3 m/s ( required  speed )

average  velocity = displacement during motion / time taken by usha 
=0m /60seconds
∴0m/s (required velocity)

Hope the answer helps!