Usha walked at the speed of 7/
3
km per hour for 2 hours and
then at the speed of
3/2 km per hour for next 2 hours. Find the
total distance walked by Usha in 4 hours
Answers
Answered by
1
Distance 1=7/3*2=14/3 km
Distance 2=3/2*2=6/2 km
LCM=6
D1=14/3*2/2=28/6km
D2=6/2*3/3=18/6km
Total Distance=D1+D2
TD=28/6+18/6
TD=46/6 km=7 whole 4/6 km
Distance 2=3/2*2=6/2 km
LCM=6
D1=14/3*2/2=28/6km
D2=6/2*3/3=18/6km
Total Distance=D1+D2
TD=28/6+18/6
TD=46/6 km=7 whole 4/6 km
kaushikvidit007:
please mark as brainliest
Answered by
0
Speed of Usha in first two hours = 7/3 km/h
Distance traveled by Usha in first two hours = Speed * time
= 7/3 * 2
= 14/3 km
= 4.667 km
= nearly 4.7 km
Speed of Usha in next two hours = 3/2 km/h
Distance traveled by Usha in next 2 hours = 3/2*2
= 3 km
Total distance traveled by Usha in 4 hours = 4.7 + 3
= 7.7 km (nearly)
Hope this helps you.
Distance traveled by Usha in first two hours = Speed * time
= 7/3 * 2
= 14/3 km
= 4.667 km
= nearly 4.7 km
Speed of Usha in next two hours = 3/2 km/h
Distance traveled by Usha in next 2 hours = 3/2*2
= 3 km
Total distance traveled by Usha in 4 hours = 4.7 + 3
= 7.7 km (nearly)
Hope this helps you.
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