Question

using (a+b)^2=(a^2+b^2+2ab),:[i] (11.6)^2​

Answer 1

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Answer:

$( {10 + 1.6})^{2}$

${10}^{2} + {1.6}^{2} + 2 \times 10 \times 1.6$

$100 + 2.56 + 32$

$134.56$

Answer 2

Answer:

$134.56$

Step-by-step explanation:

$(11.6)^{2} \\(11+0.6)^{2}\\a^{2}+2ab+b^{2}\\(11)^{2}+(2)(11)(0.6)+(0.6)^{2}\\121+13.2+0.36\\121+13.56\\134.56$

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