Question

using a horizontal force of 200N, we intend to move a wooden cabinet across a floor at a constant velocity . what is the friction forces that will be exerted on the cabinet? ​

Answer 1

Answer:

Step-by-step explanation:Force = Mass x Acceleration

For constant velocity, the net external force acting on the system should be zero.

In the vertical direction, it's weight will cancel out the normal reaction force.

In the horizontal direction, similarly, the frictional force has to cancel the applied force of 200 N. In order to do that, the frictional force should be of the same magnitude as the applied force and in a direction exactly opposite to that of the applied force.

Hence, the magnitude of the frictional force should be 200 N, and it's direction should be opposite to that of the applied force.

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Answer 2

Step-by-step explanation:

since, a horizontal force of 200N is used to move a wooden cabinet, thus a friction force of 200N will be exerted on the cabinet. Because according to third law of motion, an equal magnitude of force will be applied in the opposite direction.