Question

using a laser and soap water study the refraction of light. write a report. (plz answer)

Answer 1

Refraction of light is the phenomenon

by which a single monochromatic source of light emits a ray which is deviated

by another medium when it passes through it. This is easily seen when we look

through the side of a glass at a pencil on the other side.

Answer 2

                                                                                                                                                                           "When a beam of monochromatic light passes across "boundary between two media" the phenomenon of refraction occurs.

From the figure it is inference that the laser beam is ready to incident on visible glass container which contains soap solution

When laser beam strikes the glass container at AC and gets refracted and emerged at point E on the other side. On the opposite side a screen is kept to spot the laser light(at point F).

The distance between AB and BC is measured and noted. Where AB is the distance between laser beam exit point and the container and BC is the distance between incident point of laser beam and to the horizontal level of laser beam exit point.

Therefore

$\frac { BC }{ AB } \quad =\quad \tan { i }$

where i is angle of incidence.

Similarly, distance between the points EG, and GF is also measured

Therefore

$\frac { FG }{ GE } \quad =\quad \tan { e } \quad$

where e is angle of emergence.

"A point - D is marked  at container just opposite to C". The distance between points DE and CD (container diameter) are also measured.

Therefore, $\frac { DE }{ CD } \quad =\quad \tan { r }$  , where r is the refraction angle.

From the measured distances and angles, the incident angle (i), the emergent angle (e) and refraction angle (r) are calculated.

Therefore the refractive index of soap solution is given by  

$\frac { \sin { i }}{ \sin { r}} \quad =\quad \frac { \sin { e}}{ \sin { r }}$"