Question

Using a suitable identity evaluate (2y-6) (2y-8)

Answer 1

USING (x + a) (x + b) = x^2 - (a + b) x + a * b

so

(2y - 6) (2y - 8) = (2y)^2 - (-6 + (-8) 2y + (-6) * (-8)

4y^2 -(-14)2y + (48)

4y^2+28y+48 is our Answer

THANK YOU

Answer 2

Answer:

$\huge\mathfrak\purple{Solution}$

Solve this ques by using this property:-

$(x - a)(x - b) = {x}^{2} - (a + b)x + ab$

${2y}^{2} - ( - 6 + ( - 8)2y + ( - 6)( - 8)$

${2y}^{2} - ( - 6 - 8)2y + 48$

${2y}^{2} - ( -28y) + 48$

${2y}^{2} + 28y + 48$

Step-by-step explanation:

Hope this helps you.

# By Sparkly Princess.