Using a suitable identity find a) 97times 103 (b) (3a-4b)^(3)
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Step-by-step explanation:
(a). (100-3)(100+3)
by using identity (a-b)(a+b)=(a^2-b^2)
therefore,
= (100^2-3^2)
=10000-9
=9991
(b). using identity (a-b)^3=a^3-b^3-3ab(a-b)
=3a^3-4b^3-3(3a)(4b)(3a-4b)
=27a^3-64b^3-36ab(3a-4b)
=27a^3-64b^3-108a^2b+144ab^2
I hope you will understand
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