using a suitable pattern, evaluation the following.
1. (999999)^2
2. (6667)^2
3. (111111)^2
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Answered by
4
999,9992−1=(1000000−1)2−1=(106−1)2−1=(1012+1−2∗1∗106)−1=(1012−2∗106)=106∗(106−2)
rkshu:
sorry but i don't understand bro
Answered by
3
Answer:
1.999998000001
2.44448889
3.12345654321
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