Math, asked by rkshu, 1 year ago

using a suitable pattern, evaluation the following.
1. (999999)^2
2. (6667)^2
3. (111111)^2

Answers

Answered by Anonymous
4

999,9992−1=(1000000−1)2−1=(106−1)2−1=(1012+1−2∗1∗106)−1=(1012−2∗106)=106∗(106−2)


rkshu: sorry but i don't understand bro
Answered by MoupriyaMondal
3

Answer:

1.999998000001

2.44448889

3.12345654321

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